POSGFA1.2 of light is incident horizontally onto an equilateral prism whose refractive index is n. Note: The axis A beam of the prism is normal to this page. side 3 The light strikes Side 1 near its center, and is incident parallel to Side 3. The light exits the prism through side 2 at an angle of 90 degrees as shown. What is n?



Answer :

A deviation in the ray's path occurs at the interface when light moves from one medium to another. The term for this is refraction.

Snell's law governs it. If the ray hits the interface in a medium with a refractive index of n 2 and is incident at an angle i with the normal, and the angle of refraction is r, then n 1 sin i = n 2 sin r.

At some critical angle of incidence, the ray will travel parallel to the interface without crossing it if n 1 is greater than n 2. The ray completely transforms back into the incident medium after this angle. Total internal reflection is the term for this.

A = 60 (an equilateral prism), i = 90-60-30, and M = RI. =?

Now, fum (D r1 = 60- sin1 (1) n = n = 1 2/8460.68 (ban (1) - Cob -  (=sin(10)=0) = 3 (n2-1) = 1 = 3 (n2 1) = x2+1 2 n=1.527).

To learn more about reflection here:

https://brainly.com/question/15487308

#SPJ4

View image contexto1028
View image contexto1028

Other Questions