Use random sample of 64 drivers used on average 749 gallons of gasoline per year: The standard deviation of the population is 29 gallon. Use graphing calculator. olo Part: 0 / 2 Part 1 of 2 Find the 95% confidence interval of the mean for all drivers. Round the answers to the nearest whole number.

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12-12-2022
Mathematics

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Use random sample of 64 drivers used on average 749 gallons of gasoline per year: The standard deviation of the population is 29 gallon. Use graphing calculator. olo Part: 0 / 2 Part 1 of 2 Find the 95% confidence interval of the mean for all drivers. Round the answers to the nearest whole number.

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contexto1220 contexto1220 · Answer 1 · 2022-12-22T00:29:38-05:00

The 95% confidence interval of the mean for all drivers is the (741.527, 760.473).

Confidence program language period gives various values in phrases of bounds specifically decrease and higher that has the possibilities of containing the unknown parameter. The variety of values is decided via way of means of the usage of the pattern information values.

Here we have Given Information;

Sample length of the drivers taken (n)=36Average Gasoline used in step with yr as in step with the pattern information(¯x)=751Population trendy deviation (σ)=29Using the z-tables, the -tailed essential of z at 5% stage of importance is 1.96.
zc=1.96
The self assurance c program languageperiod for populace share may be computed as:
CI=¯x±zc×σ√n=751±1.96×29√36=(751±9.473)=(741.527,760.473)
Hence, the specified 95% self assurance c program language period is (741.527, 760.473).