assume that there is a party consisting of people between the ages of 18 and 24 inclusive. how many people would have to be at the party to guarantee that at least three people share the same birth date, birth month, and birth year? note: assume the range of birth years include 2 leap years. (

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12-12-2022
Mathematics

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assume that there is a party consisting of people between the ages of 18 and 24 inclusive. how many people would have to be at the party to guarantee that at least three people share the same birth date, birth month, and birth year? note: assume the range of birth years include 2 leap years. (

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contexto1019 contexto1019 · Answer 1 · 2022-12-18T06:41:16-05:00

The minimum number of people that would need to be at the party to guarantee that at least three people share the same birth date, birth month, and birth year is Three (3).

To find the number of people that would need to be at the party to guarantee that at least three people share the same birth date, birth month, and birth year, we need to consider the number of possible birthdays that exist within the given age range (18 to 24 inclusive).

There are 12 months in a year, and each month has between 28 and 31 days (depending on the month). Therefore, there are a total of 12 * 31 = 372 possible birthdays within a given year.

There are 7 possible birth years within the given age range (18 to 24 inclusive), which means there are a total of 7 * 372 = 2596 possible birthdays within the given age range.

Since we want to guarantee that at least three people share the same birthday, we need at least 3 people to be at the party.

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Complete Question:

Assume that there is a party consisting of people between the ages of 18 and 24 inclusive. How many people would have to be at the party to guarantee that at least three people share the same birth date, birth month, and birth year? Note: assume the range of birth years include 2 leap years.