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you throw a ball up into the air at 84 m/s. when it reaches a velocity of 32 m/s, how high above the ground is it? use 10 m/s2 for gravity and answer in m.you throw a ball up into the air at 84 m/s. when it reaches a velocity of 32 m/s, how high above the ground is it? use 10 m/s2 for gravity and answer in m.



Answer :

When it reaches a velocity of 32 m/s, it is 571.2m high above the ground.

What does velocity refer to?

Velocity is the direction speed of an item in motion as a measure of the rate at which its location is changing as seen from a certain point of view and as measured by a specific unit of time.

The movement of an object that has been launched into the air is known as projectile motion. Only gravity is felt by the item after the initial force that launches it. Projectile and trajectory both refer to the same thing: an object.

Given

Initial velocity ,u =  84m/s

Final velocity, v =  32m/s

Gravity ,g = -10m/s (upward motion, against gravity )

We know, v = u + gt

32 = 84 -10t

10t  = 84-32

t = 5.2 s

Now using, s = ut +1/2 gt^2

s = [84*5.2] +1/2[10*5.2^2]

s = 436 + 135.2

s = 571.2m

To learn more about projectile motion use link below:

https://brainly.com/question/24216590

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