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a positive point charge q is released from rest at point x. if the magnitude of the electric field at point x is e, what is the kinetic energy of the charge at point y? (a) (b) (c) (d) (e) qed 2qed 2qed 2 2qed 4qed



Answer :

K.E. = q2E2t2 / 2m is the formula of columb's law.

Law of Coulomb

The electrostatic force between two charged items is inversely proportional to the square of the distance between the two objects and directly proportional to the product of their charges.

Electrostatic force,

F = q E

m (dv/dt) = q E

Integrating, we will get,

v = q E t / m + c  

where c= integraing constant.

at t = 0, v = 0, so c = 0

now, v = q E t / m

Therefore,

K.E. =1/2 m v2

K.E. = q2E2t2 / 2m

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