The wire segment was parallel to the y-axis E = 0.72 volt ;E = 0 volt are the answer.
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Given that – Length of segment = 0.50m
1. E = L * (V x R)
E = 0.50k {(18i + 24j +72k) x (0.800j)}
E = 0.50 * 18 * 0.800 + 0
E = 0.72 volt
Thus, the motional emf will be 0.72 volt
2. If the wire segment is parallel to y-axis
E = 0.50j * {(18 x 0.080) k – (72 x 0.800) i)}
E = 0 volt
Thus, the motional emf in this situation is zero.
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