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two prospectors are pulling on ropes attached around the neck of a donkey that does not want to move. one prospector pulls with a force of 50 lb, and the other pulls with a force of 75 lb. if the angle between the ropes is 25 degrees, then how much force must the donkey use in order to stay put? 8. a cannon ball is placed on a 12 degree incline., a force of 9.6 pounds is required to keep the ball in place. determine the weight of the ball.



Answer :

Fr = 14920 is the correct answer.

Using the formula of Force

The Donkey is reportedly being dragged by two prospectors using ropes with gives of F1 = 50 lb and F2 = 75 lb and an angle of 25° between the ropes.

Therefore, the Donkey must exert force that is equivalent to and directed in the opposite direction as the force that the rope is applying to the Donkey.

Consequent force is

Fr = [tex]F1^{2}[/tex] + [tex]F2^{2}[/tex] + 2F1F2 Cos (25°)

After entering the values, we obtain

Fr = [tex]50^{2}[/tex] + [tex]75^{2}[/tex] + (2)(50)(75) Cos (25°)

Fr = 2500 + 5625+ (2)(50)(75) (0.906)

Fr = 2500 +5625 + 6795

Fr = 14920

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