Answer :
As the dielectric constant K exceeds 1, the capacitance rises. Possible variation V = CQ. The p.d. between the plates lowers as C rises while Q stays the same when the battery is disconnected.
Electric field E=dV, where d is the distance between the plates and V is the p.d. The electric field also diminishes when V lowers while d stays constant. U=21CQ2 is the energy stored in a capacitor. U declines while Q stays constant and C rises.
If the plates of a parallel plate capacitor are pulled apart while it is charging, what happens?
As the plates are separated, the distance d between them increases, which causes the capacitance to decrease. As a result, the capacitor's voltage rises as Q=CV in order to keep the charge constant.
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