Messages arrive to a computer server according to a Poisson distributionwith a mean rate of 17 per hour. Determine the length of an interval oftime such that the probability that no messages arrive during this intervalis 0.94.



Answer :

The length of an interval of time such that the probability that no messages arrive during this interval is 0.94 is 56.88 seconds.

We have to find the length of the time interval that the probability of no messages arrive during this interval is 0.94

Let X be the no.of messages arrive to the server

X follows the poisson distribution with mean λ = 17

Let t be the time interval

The probability of no messages arrive during this interval is 0.94

Then P(0) = 0.94

e⁻⁽λt⁾ = 0.94

λt = ln0.94

17 t   = ln(0.94)

t = ln(0.94)/17

t = 0.026872 / 17 hrs

t = 0.0158

Convert 0.0158 hours to seconds

That is t=0.0158(60)(60)

 =56.88seconds

Hence in 56.88 seconds the time interval that the probability of no messages arrive during this interval is 0.94 .

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