The Insure.com website reports that the mean annual premium for automobile insurance in the United States was $1,503 in March 2014. Being from Pennsylvania at that time, you believed automobile insurance was cheaper there and decided to develop statistical support for your opinion. A sample of 25 automobile insurance policies from the state of Pennsylvania showed a mean annual premium of $1,425 with a standard deviation of
s = $165.
(a)
Develop a hypothesis test that can be used to determine whether the mean annual premium in Pennsylvania is lower than the national mean annual premium.
H0: ???? > 1,503
Ha: ???? ≤ 1,503
H0: ???? < 1,503
Ha: ???? ≥ 1,503
H0: ???? ≤ 1,503
Ha: ???? > 1,503
H0: ???? = 1,503
Ha: ???? ≠ 1,503
H0: ???? ≥ 1,503
Ha: ???? < 1,503
(b)
What is a point estimate in dollars of the difference between the mean annual premium in Pennsylvania and the national mean? (Use the mean annual premium in Pennsylvania minus the national mean.)
$
(c)
At
???? = 0.05,
test for a significant difference.
Find the value of the test statistic. (Round your answer to three decimal places.)
Find the p-value. (Round your answer to four decimal places.)
p-value =
State your conclusion.
Reject H0. We can conclude that the population mean automobile premium in Pennsylvania is lower than the national mean.
Do not reject H0. We can conclude that the population mean automobile premium in Pennsylvania is lower than the national mean.
Do not reject H0. We cannot conclude that the population mean automobile premium in Pennsylvania is lower than the national mean.
Reject H0. We cannot conclude that the population mean automobile premium in Pennsylvania is lower than the national mean.



Answer :

Hypothesis test t(s) = - 1.91. We must reject the null hypothesis H₀ at confidence interval 0.95

What do you mean by Hypothesis test?

Hypothesis test: Hypothesis testing is a form of statistical inference that uses data from a sample to draw conclusions about a population parameter or a population probability distribution. First, a tentative assumption is made about the parameter or distribution. This assumption is called the null hypothesis and is denoted by H₀

Sample with a normal distribution of size <30 and n = 25 independent samples

Consequently, we can use t-student analysis.

H₀ => μ₀= 1503 is the null hypothesis in the first test.

The alternative theory is Ha =>μ₀<1503 (from problem condition)

We must now calculate t(s), where t(s) = [(μ-μ₀)/(s/√n)

μ= sample mean

s = sample standard deviation

Then t(s) is equal to (1440 - 1503) / 165 / √25 =>t(s) = - 63 * 5 / 165

t(s) = - 1.91

We now check the t-student table for t(c) (24 degrees of freedom and = 0,05) and discover that t(c) = - 1.711 ( we must remember symmetry in t-student curve)

Thus, we contrast t(s) with t(c)

t(s) = -1.91  t(c) = -1.711

t(s) is smaller than t(c)   then our point is in the rejection zone we reject H₀

Hypothesis test t(s) = - 1.91. We must reject the null hypothesis H₀ at confidence interval 0.95

To learn more about Hypothesis test visit:

brainly.com/question/17099835

#SPJ4

Other Questions