Find the distance traveled by a particle with position (x, y) as t varies in the given time interval.
x = 3sin^2(t), y = 3cos^2(t), 0 = t = 5p
Find the length of the curve.



Answer :

By The length of the curve can be found using the formula for the arc length of a parametric curve, the distance traveled by the particle is 30π.

The length of the curve can be found using the formula for the arc length of a parametric curve:

L = ∫0→5p √(dx/dt)2 + (dy/dt)2 dt

We can calculate dx/dt and dy/dt as follows:

dx/dt = 6sin(t)cos(t)

dy/dt = -6sin(t)cos(t)

Substituting these values into the formula for the arc length gives us:

L = ∫0→5p √[(6sin(t)cos(t))2 + (-6sin(t)cos(t))2] dt

= ∫0→5p 6√(sin2(t)cos2(t)) dt

= 6∫0→5p |sin(t)cos(t)| dt

= 6∫0→5p sin(t)cos(t) dt

= 6[(1/2)sin2(t) + (1/2)cos2(t)]5p

= 6[(1/2)(1) + (1/2)(1)]5p

= 6(1)5p

= 30π

Therefore, the distance traveled by the particle is 30π.

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