Answer :
The molarity of a sodium hydroxide solution is found to be 0.197 M.
A solution's molarity is its solute concentration, which is measured in moles per liter. To calculate molarities after mixing solutions, use the formula M₁V₁=M₂V₂, where M₁ is the initial concentration and M₂, is the final concentration, and V₁ and V₂ are the initial and final volume.
Given V₁ is 28.7 ml = 28.7×10⁻³ L, V₂ is 22.30 ml = 22.30×10⁻³ L, and M₂ is 0.253 M.
Then, the molarity of sodium hydroxide is,
M₁ = (M₂V₂)/V₁
M₁ = (0.253 M × 22.30×10⁻³ L)/28.7×10⁻³ L
M₁ = 0.1965 M.
The answer is 0.197 M.
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