Answer :
The final image is found to be 2.37cm in front of the eyepiece.
The focal length of the eyepiece is 2.00 cm and it is placed at a distance of 19.00 cm in front of the objective lens.
Now, we can use the lens formula to find the position of the image,
1/v - 1/u = 1/f
Where,
v is the position of the image,
u is the position of the objective in front of the eyepiece,
f is the focal length of the eyepiece.
Now, putting values,
1/v - 1/(-19) = 1/(-3)
The focal length and u are taken negative because of the sign standard sign convention of the lens.
1/v+1/19 = -1/3
Solving further,
v = -2.38 cm
So, the final image is 2.38 cm in front of the eyepiece.
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