Answer :
For the distance between q 3 and q 1, the formula is: = 3 L 0 = 3 1 L = 3 1 10 cm 14 cm. Q3 should therefore be positioned at x=14 cm along the x-axis.
For q 3, there is no equilibrium position.
between two fixed changes because one is pulling it and the other is pushing it
L is set at 10 cm, and L 0 is taken to be positive. We cancel k and q 3 and set this equal to zero as the problem specifies. As a result, we get L 0.
∣q 1\s\s ∣\s\s − \s(L+L \s0\s\s)\s∣q \s2\s\s ∣\s\s =0 ⇒(\sL \s0
L+L \s0\s
\s ) \s2\s = \s∣\s∣\s∣\s∣\s∣\s
q \s1\s
q \s2\s
∣\s∣\s∣\s∣\s∣\s\s = \s∣\s∣\s∣\s∣\s∣
+1.0 μC\s−3.0 μC
=3.0 results in L 0 after taking the square root.
L+L \s0\s
For the distance between q 3 and q 1, the formula is: = 3 L 0 = 3 1 L = 3 1 10 cm 14 cm. Q3 should therefore be positioned at x=14 cm along the x-axis.
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