a car pulls away from a stop sign with a constant acceleration. after traveling 10 m, its speed is 5 m/s. what will its speed be after traveling 40 m?



Answer :

Speed be after traveling 40 m is  10 m/s.

From kinetic equation we will have

[tex]Vf^{2}[/tex] - [tex]Vi^{2}[/tex] = 2ad

5² - Vi² = 2a × 10

after 40m distance

[tex]Vf^{2}[/tex] - [tex]Vi^{2}[/tex] = 2a × 40

here let say it start from rest

vi = 0

5² - 0 = 2a × 10

[tex]Vf^{2}[/tex] - 0  = 2a × 40

divide the two equation

[tex]Vf^{2}[/tex] /25 = 2a ×40 / 2a × 10

Vf  = 10 m/s

The rate at which an object moves in relation to a reference point is measured as its speed. It is regarded as a magnitude or scalar quantity and has no direction. The formula: can be used to calculate speed.

Speed equals Distance/Time.

Average Speed - The average speed of an object is determined by the distance it covered in a predetermined amount of time. A car's average speed over the period of an hour if it traveled 50 miles is 50 mph. The car may have experienced instantaneous speeds between 40 and 60 mph throughout that time, but its average speed was 50 mph.

Learn more about Speed here:

https://brainly.com/question/23822232

#SPJ4

Other Questions