If the half-life of the oxygen isotope [tex]O^{20}[/tex] is 15 seconds, then after one minute, 1/16 of a sample of pure [tex]O^{20}[/tex] is still present.
Assumed:
The [tex]O^{20}[/tex] half-life is 15 seconds.
According to this half-life, the reactant 8s will be reduced by half at this point.
Currently, 60 seconds equal one minute.
Then we will have 4 half-lives in 60 seconds.
Next, [tex]O^{20}[/tex] will be [tex]\frac{1}{2}^4[/tex]
[tex]\frac{1}{2}^4 =\frac{1}{16}[/tex]
As a result, [tex]\frac{1}{16}[/tex] a sample of pure [tex]O^{20}[/tex] is still present after one minute.
To learn more about isotopes, refer:-
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