Answer :

If the half-life of the oxygen isotope [tex]O^{20}[/tex] is 15 seconds, then after one minute, 1/16 of a sample of pure [tex]O^{20}[/tex] is still present.

Assumed:

The [tex]O^{20}[/tex] half-life is 15 seconds.

According to this half-life, the reactant 8s will be reduced by half at this point.

Currently, 60 seconds equal one minute.

Then we will have 4 half-lives in 60 seconds.

Next, [tex]O^{20}[/tex] will be [tex]\frac{1}{2}^4[/tex]

[tex]\frac{1}{2}^4 =\frac{1}{16}[/tex]

As a result, [tex]\frac{1}{16}[/tex] a sample of pure [tex]O^{20}[/tex] is still present after one minute.

To learn more about isotopes, refer:-

https://brainly.com/question/21536220

#SPJ4