The freezing point of the solution will be - 0.952 °C can be calculated by the molality of the solution.
Molality of the solution can be calculated as follows by :
Molality= Number of the moles of the solute / weight of the solvent in Kg
= 27.3 ×100/ 83.0 × 46.07
= 0.7m
Since the molar mass of the ethanol is 46.07g/mol
So by the formula,
The molal freezing point depression constant KF and the solute's molality, m, are used to calculate the freezing point depression, which is given by T = KFm. Rearranging results in the formula: mol solute = (m) x (kg solvent).
ΔTf = Kf ×Molality
=1.86×0.7
= 0.952
Thus, freezing point = 0−0.952
=−0.952
Hence the freezing point of the resulting solution is calculated .
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