a sample of douglas fir sapwood had a wet weight of 1315.8 g and an oven-dry weight of 612 g. calculate the moisture content of the sapwood and determine if it is a reasonable value.



Answer :

The natural outdoor usage of the wood does not exceed a moisture content of 19% .Hence, it is not a reasonable value.

Given wet weight of wood = 1315.8g

Oven dry weight = 612g

Moisture content MC% = (Wet weight of wood - Weight of Oven dry wood) / Weight of Oven dry wood × 100

(1315.8 - 612) / 612 x 100

= 703.8 / 612 x 100 = 115%

In the normal use, the moisture content of wood varies between 8% and 25% by weight. The natural outdoor usage of wood does not exceed a moisture content of 19%. Hence, it is not a reasonable value.

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