Answer :
The effect on the period of a pendulum if you double its length is the period increases by a factor of √2 and if you decrease its length of a pendulum by 5.00% the period decreases by 2.5%.
A pendulum has an initial period of 2π√L/ g and then it has some new period T2 which is 2π√L2/g
(a) Give that L2 = 2L1
So we'll substitute in 2L1 in place of L2
T2 = 2π√2L1/g = √2T1
So when doubling the length, the period increases by a factor of √2
(b) Given that length of a pendulum decreases by 5.00%
Then length of remaining pendulum = L2 = 95% L1= 0.95L1
T2= 2π√L2/g = 2π√0.95L1/g = √0.95T1 = 0.975T1
Hence it decreases by 2.5%.
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