dog sits 1.25 m from the center of a merry go round and revolves at a tangential speed of 2.0 m/s. if the dog's mass is 19.3 kg, what is the magnitude of the centripetal force on the dog?

Question

09-12-2022
Physics

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dog sits 1.25 m from the center of a merry go round and revolves at a tangential speed of 2.0 m/s. if the dog's mass is 19.3 kg, what is the magnitude of the centripetal force on the dog?

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abhinavjh321 abhinavjh321 · Answer 1 · 2022-12-16T01:09:10-05:00

Dog is seated 1.25 metres from the centre and rotates at a tangential speed of 2.0 metres per second. If the dog weighs 19.3 kg, the centripetal force acting on it will be 61.76 N.

A total net force acting on an object moving in a circular motion is known as a centripetal force.

It is given that radius(r) of the merry go round = 1.25m

tangential speed of the merry go round (v) = 2m/s

Mass of the dog (m) = 19.3kg

Centripetal acceleration (ac) is calculated as = v^2/r

So ac = (2x2)/1.25 = 3.2m/s^2

According to centripetal force(Fc) = mxac

Then Fc = 19.3 x 3.2 = 61.76N

Hence the centripetal force acting on the dog is 61.76N

To learn more about centripetal force click here https://brainly.com/question/11324711

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