There are 10 frames, thus the probability of Hoffman rolling a strike in a single frame is 0.5. The probability of Hoffman rolling a perfect game is 0.000779.
The probability of Hoffman rolling a perfect game is the sum of the probabilities of him rolling a strike in each of the 10 frames.
There are 10 frames, thus the probability of Hoffman rolling a strike in a single frame is 0.5.
To calculate the probability of Hoffman rolling a perfect game, we must multiply 0.5 by 10, which is equal to 0.5. This gives us a probability of 0.000779 or 0.000779 rounded to six decimal places.
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