g 1 mole of a monoatomic gas increases its volume from 1 to 3 while the pressure also increases from 250 to 1000. this p-v process is linear. find the involved work of this process



Answer :

The involved work done when gas  increases its volume from 1 to 3 while the pressure also increases from 250 to 1000 is 2250 joule

Work done= ΔpΔv

Work done=3×750

Work done=2250 joule

First Law of Thermodynamics: The change in total internal energy of a particular system between two states is described by the first law of thermodynamics. The first law of thermodynamics states that when heat is added to a system or when work is done, the total internal energy of the system will change. A positive result when calculating work done indicates that energy is discharged into the environment while the system is operating. If the value is negative, the environment's influence has caused the system to gain energy.

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