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a boy rides his bicycle which has wheels of radius 27.0 cm. if the boy accelerates from rest to a speed of 11.2 m/s in 24.0 s, what is the angular acceleration (in rad/s2) of the tires? (enter the magnitude.)



Answer :

The angular acceleration is 0.01533rad/s.

We are given that,

Radius = r = 27.0cm

Speed = v = 11.2 m/s

Time = t = 24.0 s

Therefore , We shall first find the linear acceleration before calculating the angular acceleration from one of the linear motion kinematics equations and the initial velocity u will be 0.

v = u + at

a = v/t

a = (11.2m/s)/(27.0×10⁻²m)

a = 0.414 ×10⁻²m/s²

Now , calculating the angular acceleration,

a = α × r

α = a/r

α =  (0.414 ×10⁻²m/s²)/(27.0×10⁻²m)

α = 0.01533rad/s

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