what inductance must be connected to a 17 pf capacitor in an oscillator capable of generating 550 nm (i.e., visible) electromagnetic waves? comment on your answer.



Answer :

The inductance that must be connected to a capacitor is 5* 10⁻²¹ H.

If f is the frequency and λ is the wavelength of an electromagnetic wave, we know the relation between them as v = f * λ

The frequency is same as the frequency of oscillation of the current in the LC circuit of the generator.

f = 1/(2π* √LC)

where, C is the capacitance

L is the inductance

So, λ/(2π* √LC) = c

Given that, λ = 550* 10⁻⁹ m

C = 17 * 10⁻² F

c is the speed of light

Making L as subject, we have

L = λ²/(4π² C* c²) = (550* 10⁻⁹)² / [4π²(17 * 10⁻²) (3* 10⁸)²] = 5* 10⁻²¹ H

To know more about inductance:

https://brainly.com/question/13112375

#SPJ4