Answer :
If a neutron moves with a speed of 0.99c, its total energy is 1.07nJ, the rest energy is 0.15nJ , and kinetic energy is 0.92nJ
Given speed of neutron (v) = 0.99c
Mass of neutron = 1.674*10-27 kg
Total energy = Rest energy +Kinetic energy
Let the Rest energy be E = mc^2
E = 1.674*10-27 kg x (3x10^8)^2 = 0.15nJ
E = 939.32MeV
Total energy (Er) = γmc^2
where γ = 1/√1-(v/c)^2
Er = E/√1-(v/c)^2 = 939.32/√1-(0.99/3x10^8)^2
Er = 939.32/√1-0.9801 = 939.32/0.1411 = 6657.12MeV = 1.07nJ
Kinetic energy ( KE) = Total energy(Er) - rest energy(E)
KE = 1.07 - 0.15 =0.92nJ
Hence the rest energy of neutron is 0.15nJ while the total energy is 1.07nJ and kinetic energy is 0.92nJ
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