Answer :

both directions can be chosen as positive in this example. The right-hand rule solves these ambiguities. The resultant remains the same at 3.2 *10^4 Tm

It is possible for the line integral to go around the loop in either direction (clockwise or counterclockwise), the vector area dS to point in either of the two normal directions and Ienc, which is the net current passing through the surface S, to be positive in either direction—but both directions can be chosen as positive in this example. The right-hand rule solves these ambiguities.

The resultant remains the same at 3.2 *10^4 Tm

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