a compound contains 27.04% sodium, 16.48% nitrogen and 56.52% oxygen what is the empirical formula of the compound?



Answer :

NNaO3  is the empirical formula of the compound, a compound contains 27.04% sodium, 16.48% nitrogen and 56.52% oxygen

⇒Find molar mass of each component: N=14.0067, Na=22.98976928, O=15.9994

⇒Convert to moles: N=1.1765797796769, Na=1.1761753530743, O=3.5295073565259

⇒Find smallest mole value: 1.1761753530743

⇒Divide all components by the smallest value: N=1.0003438489011, Na=1, O=3.0008343120781

⇒Round to closest whole numbers: N=1, Na=1, O=3

⇒Combine to get the empirical formula: NNaO3,

The scientific name for nitrogen is N, and it is an element that has no colour nor smell. The ground beneath our feet, the water we drink, and the air we breathe all contain nitrogen. In reality, nitrogen makes up the majority of the atmosphere on Earth, making up around 78% of the atmosphere.

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