Answer :
The volume occupied by 18.0 g of argon gas at a pressure of 1.32 atm and a temperature of 454 k is 12.70 m³.
The ideal gas law
An ideal gas is a theoretical gas used to study the behavior of gases. Because true gasses are complex, it is difficult for us to study their behavior. Therefore, these true gasses are simplified to ideal gasses. Because it has been simplified, even an ideal gas has simpler properties and interactions than a true gas. So, simply put, this ideal gas is a model for calculating the behavior of true gasses or real gasses.
the ideal gas law equation:
PV = nRT
Where,
P = gas pressure (N/m³ or Pa)
V = gas volume (m³)
n = moles of gas present
R = gas constant (0.082057 atm.L/mol.K)
T = temperature (K)
We have,
Mass of the gas = 18.0 g
P = 1.32 atm
Temperature = 454 K
Determine the moles of gas,
The molar mass of argon is 39.948 g/mol.
n = m/Mr
= 18.0/39.948
= 0.450 mol Ar
So, the volume occupied is:
PV = nRT
(1.32)V = (0.45) (0.082057) (454)
1.32 V = 16.76
V = 12.70 m³
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