carbon disulfide has a vapor pressure of 363 torr at 25 degrees and a normal boiling point of 46.3 degrees find the change in hvap



Answer :

The change in enthalpy of vaporization is 27.4 kJ/mol that can be calculated using Clausius-Clapeyron relation.

The Clausius-Clapeyron relation is used to characterize a discontinuous phase transition between two phases of the same constituent such as ice. The plot is drawn between 1/T vs ln P.

T1= 25+273=298 K

P1=363 Torr

T2= 46.3+273 = 319.3 K

P2= 760 Torr which is the atmospheric pressure.

By using the Clausius-Clapeyron equation,

ln(P2/P1)=ΔH/R[1/T1-1/T2]

ln (760/363)=ΔH/8.314x10^-3[1/298-1/319.3]

ΔH=27.44 kJ/mol

Therefore, the change in enthalpy of vaporization is 27.4 kJ/mol.

To learn more about enthalpy check the link below:

https://brainly.com/question/14047927

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