what is the resistance of a conductor that carries a current of 120 amperes when the potential difference between its ends is 240 volts?



Answer :

The resistance of a conductor that carries a current of 120 amperes when the potential difference between its ends is 240 volts = 2 Ω

Electrical resistance

Electrical resistance is the force that opposes the flow of current, it's a component that can reduce the speed and quantity of the flow of electrons in an electric circuit.

The formula for electrical resistance can be seen to have several components, namely R is the resistance (Ω), V is the voltage (V), and I is the current strength (A).

The equation:

R = V/I

We have,

Current strength = 120 A

The potential difference between its ends  = 240 V

So, the resistance of a conductor that carries a current of 120 amperes when the potential difference between its ends is 240 volts:

R = 240 V / 120 A

= 2 Ω

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