Answer :
At 25 K temperature, 0.950 moles of oxygen gas occupy 7.50 l and exert 2.60 atm of pressure.
Ideal gas law will be used to calculate the temperature -
PV = nRT, where Pis pressure, V is volume, n is number of moles, R is gas constant and T is temperature. The value of gas constant to be used in the formula is 0.082 L atm/mol/K
Temperature = (2.60×7.5)/(0.082×0.95)
Performing multiplication in both numerator and denominator on Right Hand Side of the equation
Temperature = 19.5/0.78
Performing division on Right Hand Side of the equation
Temperature = 25 K
Thus, the temperature of oxygen gas is 25 K.
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