Answer :
Grams of SrCl2 required to make 250 ml of a 0.100 srcl2 aqueous solution is 6.76 g.
We start by calculating the number of moles of SrCl2 in 558 mL of a 0.100 M solution.
0.025 mol SrCl2 per 1 liter (mol SrCl2=0.250 0.1 mol)
We can convert the above amount from moles to grams using the molar mass of SrCl2.
0.025 mol SrCl2 158.53 g1 mol
SrCl2 = 3.96 g SrCl2
MW SrCl2 = 158.53 gmol
The resulting bulk is made up entirely of solute. We calculate the mass of solid mixture required as given, assuming that the sample of SrCl2 we have is 58.6% by weight.
Mass of the solid mixture = mass of the solute/mass% ×100,
=3.96g / 58.6 ×100,
=6.76 g SrCl2.
Thus, we require 6.76 g of a solid SrCl2 mixture that is 58.6% Sr by weight.
For more information on molarity kindly visit visit to
https://brainly.com/question/8732513
#SPJ4
