a chemist needs to prepare 2.50 l of a 0.350 m solution of potassium permanganate (kmno4 ). what mass of kmno4 does she need to make the solution?



Answer :

Mass of kmno4 does she need to make the solution is 128.375 g.

Data:-

Volume = 2.5 L

Concentration = 0.325 M

Potassium permanganate (Molar mass )= 39 + 55 + (16 x 4) = 158 g

Calculate the moles of KMnO₄

Formula

Molarity = moles/volume

moles = molarity x volume

moles = 0.325 x 2.5

moles = .8125

Calculate the grams of KMnO₄

                   158 g KMnO₄ ------------------ 1 mol

                      x     ------------------ .8125

                           x = (1.95 x 158)/1  

                         x = 128.375 g

What distinguishes mole molarity from molality?

The amount of a solute in moles to all the liters of a solution is known as its molarity. The solvent and solute are both present in the solution. The ratio of the moles of a solute to the kilograms of a solvent is known as molality, on the other hand.

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