Answer :
A) f= 2/7mgsin∅ frictional force is exerted on the ball, B) u= 2/7gtan∅ coefficient of friction is required to prevent slipping. A solid ball of inertia m rolls without slipping down a ramp that makes an angle θ with the horizontal.
Part a)
Force equation is given as
mg sin∅-f= ma
now for torque equation of the ball
f R= 2/5 R²(a/R)
f=2/5 ma
now from above two equations
mg sin∅-2/5 ma=ma
mg sin∅+7/5 ma
a=5/7 g sin∅
so frictional force is given as
f=2/5 ma
f= 2/5m (5/7sin∅)
f=2/5 mg sin∅
Part b)
We also understand that when motion is moving normally, we have
Fn= mg cos∅
so we have
f=uFn
2/7 mg sin∅= u(mg cos∅)
now we have
u= 2/7 g tan∅
A solid ball of inertia m rolls without slipping down a ramp that makes an angle θ with the horizontal. a. What frictional force is exerted on the ball?b. As a function of θ, what coefficient of friction is required to prevent slipping?
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