the heat of vaporization of water at 100°c is 40.66 kj/mol. calculate the quantity of heat that is absorbed/released when 7.00 g of steam condenses to liquid water at 100°c.

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09-12-2022
Chemistry

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the heat of vaporization of water at 100°c is 40.66 kj/mol. calculate the quantity of heat that is absorbed/released when 7.00 g of steam condenses to liquid water at 100°c.

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jaspreetsharma jaspreetsharma · Answer 1 · 2022-12-18T01:27:40-05:00

the heat of vaporization of water at 100°c is 40.66 kj/mol, Heat of vaporisation (HV) = q/m = 40.66 kJ/mol, quantity of heat is = 20.33 kjoules

q is heat absorbed or released , m is mass = 9 g, no. of moles of water = mass/mol wt = 9/18 = 0.5 moles, HV x m = q, uantity of heat is = 40.66 x 0.5 = 20.33 kjoule. The enthalpy of vaporisation, also known as the heat of vaporisation or heat of evaporation, is the amount of energy required to convert a liquid substance into a gas. The enthalpy of vaporisation depends on the pressure at which the transformation occurs. The heat of vaporisation is defined as the amount of heat required to convert 1g of a liquid into a vapour without causing the liquid's temperature to rise. Boiling refers to vaporisation at the boiling point. A boiling liquid's temperature remains constant until all of the liquid has been converted to a gas.

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