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An adult inhales about 6.0×10^−4 m^3 of fresh air during a breath. only 20% of fresh air is oxygen. assume the pressure in the lungs is 1.0×10^5 pa and the air is at a temperature of 300 k. How many oxygen molecules are in each breath?



Answer :

Number of oxygen molecules in each breath is 2.9X10^21

Given that the volume of air inside a breath (V) = 6.0×10^−4 m^3

oxygen in fresh air = 20%

volume of oxygen in fresh air = 20/100 x 6.0×10^−4 = 1.2x10-4m^3

pressure in the lungs (P)=  1.0×10^5 pa

Temperature of air (T) =300K

Using ideal gas equation find the number of moles of oxygen

PV = nRT

Then n = 1.0×10^5 x  1.2x10-4 / 8.314 x 300 = 4.8x10-3mol

We know the number of molecules in 1 mol is 6.023x10^23

Then the number of molecules in 4.8x10-3mol of oxygen is =

4.8x10-3molx 6.023x10^23 = 2.9x10^21

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