Sherwin and Lia are playing bumper car at town fair. Sherwin and hi cart have a ma of 150 kg. Lia and her cart have a ma of 95 kg. Sherwin i topped when Lia, moving at a velocity of 12 m/, collide with him. If Lia come to a complete top after the colliion, then what i Sherwin' reulting velocity after the colliion?

Question

09-12-2022
Physics

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Sherwin and Lia are playing bumper car at town fair. Sherwin and hi cart have a ma of 150 kg. Lia and her cart have a ma of 95 kg. Sherwin i topped when Lia, moving at a velocity of 12 m/, collide with him. If Lia come to a complete top after the colliion, then what i Sherwin' reulting velocity after the colliion?

Answer :

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contexto1025 contexto1025 · Answer 1 · 2022-12-14T00:17:31-05:00

Sherwin's resulting velocity after the collision is 18.94m/sec. if his initial velocity is 12m/sec and mass of 150kg.

It is given that Sherwin has initial velocity and Lia is going to start the bumper car. It means that initial velocity of Sherwin is 12m/sec and initial velocity of Lia is 0m/sec. Since, the collision is elastic, it means that energy will not lost during the collision and momentum will remain conserved.

So, applying the law of conservation of momentum which is

Initial momentum =Final momentum

=>Initial momentum of Sherwin is=mass × velocity

=>Initial momentum of Sherwin=150 × 12m/sec

Now, initial momentum of Lia is =mass × velocity

=>Initial momentum of Lia is =95×0=0m/sec

Now, final momentum of Sherwin=0m/sec since collision is elastic

Also, final momentum of Lia is =95×v

According to the formula, we get

=>150 × 12 +0 =0 + 95×v

=>95×v=150 × 12

=>v=(150 × 12)/95

=>v=1800/95

=>v=18.94m/sec

Hence, Sherwin velocity is 18.94m/sec.

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