A 48 cm long metal rod is oriented horizontally in a uniform magnetic field with magnetic flux density of 340 g. The magnetic field is directed vertically down into the ground. The metal rod is moved with a speed of 13 m/s in a horizontal direction perpendicular to the length of the rod. Neglect the magnetic field of earth at the location of this apparatus. Determine the potential difference induced in the rod. Calculate the answer in the units of v. Write your answer in decimal form with three digits to the right of the decimal point (e. G. 5. 374); do not write any units

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09-12-2022
Physics

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A 48 cm long metal rod is oriented horizontally in a uniform magnetic field with magnetic flux density of 340 g. The magnetic field is directed vertically down into the ground. The metal rod is moved with a speed of 13 m/s in a horizontal direction perpendicular to the length of the rod. Neglect the magnetic field of earth at the location of this apparatus. Determine the potential difference induced in the rod. Calculate the answer in the units of v. Write your answer in decimal form with three digits to the right of the decimal point (e. G. 5. 374); do not write any units

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febyyyvaalentina febyyyvaalentina · Answer 1 · 2022-12-17T08:51:13-05:00

The potential difference induced in the rod is approximately -6.912 v. In general, the potential energy of an object is equal to the work done to move the object to its current position, against the forces acting on it.

Potential energy is a form of energy that an object possesses due to its position in a gravitational field or due to its configuration. It is the energy that an object has due to its position in a system, rather than its motion.

The potential difference induced in the rod is given by Faraday's law of electromagnetic induction:

ΔV = -(BLv)

where B is the magnetic flux density, L is the length of the rod, and v is the speed at which the rod moves through the magnetic field.

Plugging in the given values, we have:

ΔV = -(340 g * 48 cm * 13 m/s)

Converting the length to meters and the magnetic flux density to teslas, we have:

ΔV = -(0.34 T * 0.48 m * 13 m/s)

= -6.912 v

So the potential difference induced in the rod is approximately -6.912 v.

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