Answered

the moon has a mass of 7.35×1022kg and a radius of 1.74×106m. it orbits around the earth at a distance of 3.84×108m, completing a full rotation every 27.3days. it also spins on its axis at a rate such that the same side of the moon is always facing the earth.• What is the angular momentum of the Moon in its orbit around Earth in kg-m²/s?o Lorb = 1• What is the angular momentum of the Moon in its rotation around its axis in kg-m/s?• How many times larger is the orbital angular momentum than the rotational angular momentum for the Moon?



Answer :

The angular momentum of the moon in its orbit around the earth is 28854.80* 10³⁰ kg.m²/s.

Given that,

Mass of the moon = 7.35 * 10²² kg

Radius of the orbit = 3.84 * 10⁸ m

Let us find the tangential velocity,

v = 2π* r/ T = (2π* 3.84 * 10⁸ )/ 2.36 * 10⁶ = 1022.35 m/s

T is transformed from days to seconds.

T = 27.3 * 86400 sec/ 1 day = 2.36 * 10⁶ s

The formula to find out angular momentum is, L = r *m* v

where, L is the angular momentum

r is the radius

m is the mass

v is the tangential velocity

L = 3.84 * 10⁸ * 7.35 * 10²² * 1022.35 = 28854.80* 10³⁰ kg.m²/s

Thus, the angular momentum of the moon in its orbit around the earth is 28854.80* 10³⁰ kg.m²/s.

To know more about angular momentum:

https://brainly.com/question/29159511

#SPJ4

Other Questions