Answer :

The solubility product is the equilibrium constant for the dissolution in a substance.

We know that the molar solubility of the salt x

For the salt AB(s) ⇄ A^+(aq) + B^-(aq)

[ A^+] = [B^-] = x

Ksp = [ A^+] [B^-] = x^2

For the salt AB2(s) ⇄ A^+(aq) + 2B^-(aq)

Ksp =  [ A^+] [2B^-]^2 =  [ x] [2x]^2 =4x^3

For the salt AB3(s) ⇄ A^+(aq) + 3B^-(aq)

Ksp =  [ A^+] [3B^-]^3 =  [ x] [3x]^3 = 27x^4

For the salt A3B2(s) ⇄ A^+(aq) + 3B^-(aq)

Ksp =  [ 3A^+] [2B^-]^3 =  [ 3x]^3 [2x]^2 = 108x^5

What is equilibrium constant?

  • The equilibrium constant of a chemical reaction is the value of its reaction quotient at chemical equilibrium, the state to which a dynamic chemical system approaches after a sufficient period of time when its composition has no measurable tendency to change further.

To know more about equilibrium constant, click the link given below:

https://brainly.com/question/3159758

#SPJ4