A 25-gram block of Aluminum ha an initial temperature of 35 degree Celciu. What will be the final temperature of the aluminum block with the addition of 503. 38 Joule of heat?



Answer :

If A 25-gram block of Aluminum has an initial temperature of 35 degree Celcius. The final temperature will be  57.37°C

What is the specific heat constant?

The amount of energy needed to raise the temperature of 1 kilogram of tissue by 1 K (=1°C) is measured by the specific heat capacity of tissue, or c [J/(kg K)]. For instance, fat has a lower specific heat capacity than other soft tissues, which means that it needs less energy to raise temperature. The energy needed to increase the temperature of 1 m3 of tissue by 1 K (=1°C) can be found by multiplying specific heat capacity by mass density (c [J/(m3 K)]), which is the same as a volume-specific heat capacity.

The final temperature can be calculate as follows:

Accordingly, the amount of energy generated is equal to the system's mass times its temperature change and times its specific heat.

Q=mcΔT

where,

Q= the amount of energy generated

m = mass

c = spesific heat

ΔT= temperature change

so, ΔT= final temperature - initial temperature =(x−35) °C

Therefore,

Q=mcΔT

503.38 = 25 × 0.9 × (x - 35)°C

(x - 35) =  503.3 / 25 × 0.9

x = 57.37°C

To know more about specific heat capacity, visit

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