Answer :
Distance d from the car at which the sound from the stereo can still be discerned are= 97720.5 m
Briefly:-
The link between sound intensity at a distance and distance is (power of sound at source)/ (surface area of the wall of an imaginary sphere at the distance in question)
I = P/4πd²
Assuming the car has 2 speakers,
P = 0.06 W × 2 = 0.12 W
d = ?
the intensity of the least discernible sound is
I = 10⁻¹² W/m²
10⁻¹² = 0.12/4πd²
d = 97720.5 m
What is the volume of the sound?
Sound intensity level is a unitless quantity that indicates how loud a sound is in comparison to a predetermined benchmark. The ratio of the pressure amplitude to a reference pressure is known as the sound pressure level.
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