Answer :
The depth of the ice was found to be 26.55 x 10 ^ 12 m.
What exactly are radio waves?
A transmitter emits nonparticulate radiation, which is sensed by a receiver. An antenna allows a transmitter to transfer energy into house and a receiver to pick up energy from space. Transmitters and receivers are typically designed to operate on a limited range of frequencies.
The ice depth is then 26.55 x 1012 m.
Let's call the radio wave's speed 'v.'
Let the frequency of the radio wave be represented as 'f'.
Let's call the radio wave's distance's.'
Let's call the radio wave's time period 't.'
Distance formula:
v=s/t
v=s/1/t
The inverse of time period is frequency. As a result, 1/t in the preceding formula can be substituted by f.
v=sxf
filling in the blanks in the above equation
t = 32.9 x 10 ^ -6
v = 1.7 x 10 ^ 8 x m / s
Then, f = 1 / t
Then, f = 1 / t
f= 1/3.2 x 10 - 6 s - So,
s = 1.7 x 10 x 1/3.2 x 10-
= 1.7/3.2 x 10 (8 + 6)
= 0.531 x 10 14
= 53.1
The depth of the ice would therefore be s/2 since the wave covers the distance twice in the specified time period.
Ice depth = 53.1 x 1012/2
Ice depth = 26.55 x10 12 x m
26.55 x 10 ^ 12 x m
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Additionally, the radio wave is moving at the speed of light, or 3 10 8 m/s. As a result, radio waves travel for 12.58 minutes.
What exactly are radio waves?
A transmitter emits nonparticulate radiation, which is sensed by a receiver. An antenna allows a transmitter to transfer energy into house and a receiver to pick up energy from space. Transmitters and receivers are typically designed to operate on a limited range of frequencies.
The ice depth is then 26.55 x 1012 m.
Let's call the radio wave's speed 'v.'
Let the frequency of the radio wave be represented as 'f'.
Let's call the radio wave's distance's.'
Let's call the radio wave's time period 't.'
Distance formula:
v=s/t
v=s/1/t
The inverse of time period is frequency. As a result, 1/t in the preceding formula can be substituted by f.
v=sxf
filling in the blanks in the above equation
t = 32.9 x 10 ^ -6
v = 1.7 x 10 ^ 8 x m / s
Then, f = 1 / t
Then, f = 1 / t
f= 1/3.2 x 10 - 6 s - So,
s = 1.7 x 10 x 1/3.2 x 10-
= 1.7/3.2 x 10 (8 + 6)
= 0.531 x 10 14
= 53.1
The depth of the ice would therefore be s/2 since the wave covers the distance twice in the specified time period.
Ice depth = 53.1 x 1012/2
Ice depth = 26.55 x10 12 x m
26.55 x 10 ^ 12 x m
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