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A uniform beam of length L and mass M has its lower end pivoted at P on the floor, making an angle θ with the floor. A horizontal cable is attached at its upper end B to a point A on a wall. A box of mass M is suspended from a rope that is attached to the beam one-fourth L from its upper end.
25% Part (a) Write an expression for the y-component Py of the force exerted by the pivot on the beam.
Py = 25% Part (b) Write an expression for the tension T in the horizontal cable AB
T = |
25% Part (c) Write an expression for the x-component Px of the force exerted by the pivot on the beam, in terms of T.
Px = |
25% Part (d) What is the tension in the horizontal cable, in newtons, if the mass of the beam is 48 kg, the length of the beam is 8 m, and the angle is 36°?
T = |
Please answer all the parts



Answer :

A uniform beam is suspended horizontally through two same vertical springs which can be connected among the ceiling and quit of the beam.

In physics, a force is a power that may trade the motion of an object. A pressure can purpose an item with mass to alternate its speed, i.e., to boost up. pressure can also be described intuitively as a push or a pull. A force has both importance and course, making it a vector quantity.

Pv = 2Mg

T = 0.5cos(0)Mg + 3/4 Mg cos0/sin0

Px = T

M = 48 kg, L = 8 m , 0 = 36°

T = 0.5 cos 36° × 48 * 9.8 + 3/4 × 48 × 9.8 cos 36°/sin36°

T = 875.84 N.

Force is defined as an external cause that adjustments or has a tendency to change the kingdom of the frame as soon as implemented. If the body is in motion, it comes to relaxation, and if at rest, then it's going to come to motion.

Learn more about theta here :-

brainly.com/question/19800786

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