The amount of energy stored in the capacitor is c)increases as the bulb stays lit the same amount of time. So, correct option is c.
Work must be finished to move charges onto a guide, against the power of shock from the generally existing charges on it. This work done to charges from one plate to the next is put away as expected energy of the electric field of the conveyor.
The bulb will illuminate for a moment when the capacitor begins charging. At first when key is shut, the capacitor goes about as short out, so bulb will illuminate. In any case, at last the capacitor turns out to be completely energized, so it will go about as open circuit, so bulb won't gleam.
Hence, correct option is c.
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(Complete question) is:
A Power С Supply Students perform an experiment by connecting a capacitor and a light bulb to a variable power supply in the circuit shown. The switch is closed to position A, the capacitor becomes fully charged, and then the switch is moved to position B and allowed to fully discharge. What happens to the amount of energy stored in the capacitor as the voltage of the power supply is increased, and what evidence supports this claim?
a)The energy increases as the bulb stays lit a shorter amount of time.
b) The energy increases as the bulb stays lit a longer amount of time.
c) The energy increases as the bulb stays lit the same amount of time. d)The energy decreases as the bulb stays lit a shorter amount of time.
e )The energy decreases as the bulb stays lit a longer amount of time.
