A simple pendulum consisting of a bob of mass m attached to a string of length L swings with a period T. If the bob's mass is doubled, approximately what will the pendulum's new period be?

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08-12-2022
Physics

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A simple pendulum consisting of a bob of mass m attached to a string of length L swings with a period T. If the bob's mass is doubled, approximately what will the pendulum's new period be?

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qwcherry qwcherry · Answer 1 · 2022-12-15T01:45:43-05:00

The pendulum's new time period is T.

A bob suspended at the end of a thread that is so light as to be regarded massless makes up a simple pendulum. It serves as an example of a conservative oscillatory system. A point mass m anchored to one end of a massless rod of length L makes up this idealized representation of a pendulum.

The time period of a simple pendulum is calculated by the formula, [tex]T=2\pi\sqrt{\frac{L}{g}}[/tex] where T is the time period, L is the length of the pendulum, and g is the acceleration due to gravity. Since this formula is independent of mass, the change in the mass of the bob doesn't affect the time period. Therefore, the new time period will still be T. There is no change.

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