Answer :
Then the depth of the ice is 26.55 x 10¹² m
Let speed of the radio wave be represented as 'v'
Let frequency of the radio wave be represented as 'f'
Let distance of the radio wave be represented as 's'
Let time period of the radio wave be represented as 't'
From the formula for distance:
v=s/t
v= s x 1/t
Frequency is the inverse of time period. So, 1/t in the above formula can be replaced by f.
v = s x f
putting values in the above equation
t = 32.9 x 10⁻⁶ s
v = 1.7 x 10⁸ m/s
The, f = 1/t
f = 1/3.2 x 10⁻⁶ s⁻,
So,
s = 1.7 x 10⁸ x 1/3.2 x 10⁻⁶
= 1.7/3.2 x 10⁸⁺⁶
= 0.531 x 10¹⁴
= 53.1 x 10¹²
Then the depth of the ice would be s/2 as the distance is covered twice by the wave in the given time frame.
Depth of ice = 53.1 x 10¹²/2
Depth of ice = 26.55 x 10¹² m
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