Answer :
When a system absorbs 2,500 J of heat and exerts 7,655 J of work on its surroundings, its internal energy changes by - 5,155 J.
The fundamental concepts of internal energy, heat, and system work are used in the derivation of the first law of thermodynamics. According to this thermodynamic law, the change in internal energy of the system is equal to the heat contributed to a system minus the work done by the system.
The formula for this is given as ΔU = Q - W where ΔU is the change in internal energy, W is work done by the system, and Q is the heat added to the system.
Given the heat absorbed is 2,500 J and the work done is 7,655 J. Then, the change in the internal energy is,
ΔU = 2,500 J - 7,655 J = -5,155 J.
The answer is -5,155 J.
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