Answer :
The percentage of the iceberg that is visible above the water's surface will be 11.5% if specific gravity of ice is 0.917.
We know very well that density is defined as the division of mass with per unit volume. It is an important factor in order to find the fluid and its properties. Its SI.unit is kg/m³.
We know very well that the mass and density relation is given by the formula
mass = density × volume
We are given density of ice = 917 kg/m³,density of the seawater=1025 kg/m³
Therefore, the ratio by which the iceberg submerge is found as
=>[tex]V_s[/tex]/V=ρ/ρ[tex]_o[/tex]
where V and ρ is defined as the volume of the iceberg and ρ is defined as the density of the substance.
=>[tex]V_s[/tex]/V=0.917/1.025
=>[tex]V_s[/tex]/V =917/1025
=>[tex]V_s[/tex]/V=0.895
or we can 89.5% of ice is submerged inside the water.
But we need to find the percentage which is visible to us, it means we need to subtract the submerged percentage from total percentage possible.
⇒The percentage which is visible to us=100-.89.5 %
⇒The percentage which is visible to us=11.55 %
To learn more about the density, visit here:
brainly.com/question/952755
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