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A 8.0-m long wire with a mass of 10 g is under tension. a transverse wave for which the frequency is 570 hz, the wavelength is 0.10 m, and the amplitude is 3.7 mm is propagating on the wire. the maximum transverse acceleration of a point on a wire is closest to?



Answer :

ayune

The maximum transverse acceleration of a point on a wire is closest to 47,410 m/s²

The general wave function is:

y = A cos (ωt + Ф)

Where:

A = Amplitude

ω = angular frequency = 2πf

Ф = phase angle

The transverse acceleration is the second derivative of the above function:

a = d²y/dt²

  = -  ω²A cos (ωt + Ф)

Hence, the maximum transverse acceleration is:

a_max = ω²A

           = (2πf)²A

           = 4π²f²A = 4 x 3.14² x 570² x 3.7 mm/s²

           =  47,410 m/s²

Learn more about wave function here:

https://brainly.com/question/28448050

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